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0=0.4n^2+0.6n-378
We move all terms to the left:
0-(0.4n^2+0.6n-378)=0
We add all the numbers together, and all the variables
-(0.4n^2+0.6n-378)=0
We get rid of parentheses
-0.4n^2-0.6n+378=0
a = -0.4; b = -0.6; c = +378;
Δ = b2-4ac
Δ = -0.62-4·(-0.4)·378
Δ = 605.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.6)-\sqrt{605.16}}{2*-0.4}=\frac{0.6-\sqrt{605.16}}{-0.8} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.6)+\sqrt{605.16}}{2*-0.4}=\frac{0.6+\sqrt{605.16}}{-0.8} $
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